A 4 kva, 400 v/200 v single phase transformer has resistance of 0.02 p.U and reactance of 0.06 p.U. The resistance and reactance referred to hv side are
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The bases of physical transformer resistance (T/F). So the induction between the two circuits with a common magnetic field in a statistical device.
The applied voltage V1 opposes E1,
While E2 provides the second output voltage V2.
E1/E2 = I2/I1 = T1/T2
R2+jX2=0.02 ohm+j0.06 ohm
a=V2/V1=200/400=0.5
R2'+jX2'=(R2+jX2)/(a^2)=0.08 ohm and 0.24 ohm
The resistance and reactance referred to hv side is 0.08 ohm and 0.24 ohm
Answered by
16
V₁I₁ = V₂I₂
Z₁ = V₁/I₁
Z₂=V₂/I₂
V₁ = 400 V
V₂ = 200V
I₁ = P/V₁ = 4/400
I₂ = P/V₂ = 4/200
Z₁ = 400/(4/400) = 40000
Z₂ = 200/(4/200) = 10000
Z₁ = 4Z₂
Primary side is HV side
4 * 0.02 = 0.08 pu
4 * 0.06 = 0.24 pu
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