Physics, asked by amanprasad735, 1 year ago

A 4 kva, 400 v/200 v single phase transformer has resistance of 0.02 p.U and reactance of 0.06 p.U. The resistance and reactance referred to hv side are

Answers

Answered by techtro
16

The bases of physical transformer resistance (T/F). So the induction between the two circuits with a common magnetic field in a statistical device.

The applied voltage V1 opposes E1,

While E2 provides the second output voltage V2.

E1/E2 = I2/I1 = T1/T2

R2+jX2=0.02 ohm+j0.06 ohm

a=V2/V1=200/400=0.5

R2'+jX2'=(R2+jX2)/(a^2)=0.08 ohm and 0.24 ohm

The resistance and reactance referred to hv side is 0.08 ohm and 0.24 ohm

Answered by amitnrw
16

V₁I₁ = V₂I₂

Z₁ = V₁/I₁

Z₂=V₂/I₂

V₁ = 400 V

V₂ = 200V

I₁ = P/V₁ = 4/400

I₂ = P/V₂ = 4/200

Z₁ =  400/(4/400) = 40000

Z₂ = 200/(4/200) = 10000

Z₁ = 4Z₂

Primary side is HV side

4 * 0.02 = 0.08 pu

4 * 0.06 = 0.24 pu

Similar questions