A 4 kva, 400 v/200 v single phase transformer has resistance of 0.02 p.U and reactance of 0.06 p.U. The resistance and reactance referred to hv side are
Answers
Answered by
16
The bases of physical transformer resistance (T/F). So the induction between the two circuits with a common magnetic field in a statistical device.
The applied voltage V1 opposes E1,
While E2 provides the second output voltage V2.
E1/E2 = I2/I1 = T1/T2
R2+jX2=0.02 ohm+j0.06 ohm
a=V2/V1=200/400=0.5
R2'+jX2'=(R2+jX2)/(a^2)=0.08 ohm and 0.24 ohm
The resistance and reactance referred to hv side is 0.08 ohm and 0.24 ohm
Answered by
16
V₁I₁ = V₂I₂
Z₁ = V₁/I₁
Z₂=V₂/I₂
V₁ = 400 V
V₂ = 200V
I₁ = P/V₁ = 4/400
I₂ = P/V₂ = 4/200
Z₁ = 400/(4/400) = 40000
Z₂ = 200/(4/200) = 10000
Z₁ = 4Z₂
Primary side is HV side
4 * 0.02 = 0.08 pu
4 * 0.06 = 0.24 pu
Similar questions
Biology,
6 months ago