A 4 m long car goes past a 5 m long bus at rest on the road the speed of the car is 9 m/s. Then the car taken time to go past the bus is
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Answer: 1s
Explanation:
If we keep car’s starting point (headlight part) with the bus’ back, we will get that car first has to travel 5m to be at the same position with the bus, but, to pass it car’s back should be aligned with bus’ front thus resulting more 4m more travel. Thus,
Total Distance= (4+5)m = 9m
Speed of Car= 9m/s
Time = Distance/Speed= 9/9 = 1s
Hope it helps...
Explanation:
If we keep car’s starting point (headlight part) with the bus’ back, we will get that car first has to travel 5m to be at the same position with the bus, but, to pass it car’s back should be aligned with bus’ front thus resulting more 4m more travel. Thus,
Total Distance= (4+5)m = 9m
Speed of Car= 9m/s
Time = Distance/Speed= 9/9 = 1s
Hope it helps...
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