(a)
4
ਹੇਠਾਂ ਲਿਖਿਆਂ ਨੂੰ ਮਿਲਾਉ:- Match the following:-
(1) ਤਿਭੁਜ ਦੇ ਸਿਖਰ (Number of vertices of triangle)
(ii) ਚਤੁਰਭੁਜ ਦੇ ਸ਼ਿਖਰ (Vertices of quadrilateral)
(iii) ਰੇਖਾਖੰਡ ਦੇ ਸਿਖਰ (Vertices of line segment)
(iv) ਪੰਜਭੁਜ ਦੇ ਸਿਖਰ ( Vertices of pentagon)
(b) 3
(c)
5
(d) ਕੋਈ ਨਹੀਂ
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2
Answer:
we have to compare the quadratic equation, 2y² = 9y with the standard form and find the values of a, b and c.
solution : quadratic equation is 2y² = 9y
⇒2y² - 9y + 0 = 0
standard form of quadratic equation is ay² + by + c = 0
on comparing
⇒2y² + (-9)y + 0 = ay² + by + c
here , coefficient of y² of 2y² + (-9y) + 0 = coefficient of y² of ay² + ay + c
i.e., 2 = a
coefficient of y of 2y² + (-9)y + 0 = coefficient of y of ay² + by + c
i.e., -9 = b
constant of 2y² + (-9)y + 0 = constant of ay² + by + c
i.e., 0 = c
Therefore a = 2 , b = -9 and c = 0
Step-by-step explanation:
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