a 4 ohm wire is double on it. what is its new resistance
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if you half the length and Cross section area doubled then resistance becomes R=rho *l/A
new resistance=rho*l/2/2A
then resistance becomes 4 times
then the new resistance is 4*4=16 ohm
new resistance=rho*l/2/2A
then resistance becomes 4 times
then the new resistance is 4*4=16 ohm
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length Half and cross-sectional area doubled
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