Question

A 4% solution (w/w) of sucrose ( M = 342g/mol) in water has a freezing point of 271. 15 k. Calculate the freezing point of 5% glucose ( M = 180g/mol ) in water.
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Answer 1

Answer:

Hi...

Here's ur answer...

Answer :

4% solution (w/w) of sucrose means 4g of sucrose in 96g water

Wsolvent = 96g, wsolute= 4g, Msolute= 342 g mol-1

Using the formula, ∆Tf = kf x m

(273.15 – 271.15) = 16.39

Kf = 16.39 K

For 5% solution (w/w) of sucrose means 5g of sucrose in 95g water

Wsolvent = 95g, wsolute= 5g, Msolute= 180 g mol-1

Using the formula, ∆Tf = kf x m

∆Tf = 0.48K

= 0.48 K

Tf = Tf0 - ∆Tf = (273.15 – 0.48) K = 272.67 K

hope it helps..✌❤...