A 4 v battery is used
Find
1.total current
2.pd over 12 ohm resistor
3.current over 6 ohm resistor
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1. V=IR
4=I×6
l=0.66A
2.V=IR
V=0.66×12
V=7.92V
3.Rs=6+6=12ohm
Rs=12+12=24ohm
1/Rp = 1/12 + 1/24
1/Rp = 3/24
Rp = 8ohm
V=IR
4=I×8
I=0.5A
Explanation:
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