Question

a=4(x+2), b=(x+3), c=25(hypotenuse)
Find the value of x by using pythagores' theorem.

Answer 1

Solution:-
a = 4(x+2), b= (x+3) and c = 25
a² + b² = c²
{4(x+2)}² + (x+3)² = (25)²
16(x²+4+4x) + (x²+9+6x) = 625
16x²+64+64x+x²+9+6x = 625
17x²+70x+73 = 625
17x² + 70x - 625 + 73 = 0
17x² + 70x - 552 = 0
x =  - 70 + √4900+37536
              - 
       ________________ 
                 2 × 17

= - 70 + √42436
          - 
    ____________
           34

= (- 70 + 206)/34 
          136/34
x = 4
Answer.