Question

A=4(x+3) au carré+3x(x+2)+(x+2) (x-2)

Answer 1

Answer:

Given that,

 (x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

⇒x  

2

+2x+3x+6+x  

2

−3x−2x+6−2x  

2

−2x=0

⇒2x  

2

−2x  

2

+5x−5x−2x+12=0

⇒−2x+12=0

⇒−2x=−12

⇒x=6