Question

A 40.0 ml volume of 1.80 M Fe(NO3) is mixed with 21.5ml of 0.808 M Fe(NO3) solution. calculate the molar concentration of the final solution​

Answer 1

Answer:

by equating the number of moles of initial and final solution

the molarity of the final solution is 1.4 mol / L

Answer 2

Answer:

M 3 = 1 .4 5 M

Explanation:

M 3 = 1 .4 5 M

Is the answer of this question .

Given: A 40.0 ml volume of 1.80 M Fe(NO3) is mixed with 21.5ml of 0.808 M Fe(NO3) solution.

To find: calculate the molar concentration of the final solution​

Solution:

Let's use a slightly different way to write the subscripts:

M 1 V 1  +  M 2 V 2 = M 3 V 3

There is no standard way to write the subscripts in problems of this type.

Substituting:

( 1.80 )  ( 40.0 ) + ( 0.808 ) ( 21.5 ) = ( M 3) (40.0 + 21 .5 )

M 3 = 1 .4 5 M

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