A 40 cm long spring becomes 47 cm when a load of 10 N hangs from its free end. Determine the force constant of the spring
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Answer:
142.86 N/M
Explanation:
Let F be the force applied on the spring , e be the extension of the spring and k be the spring constant.
We have the formula as follows :
k = F/e
The F is in Newtons, e is in meters.
From the question :
F = 10 N
e = 47 - 40 = 7 cm
We convert this to meters.
1 meter = 100 cm
= 7/100 = 0.07 meters
Doing the substitution we have :
k = F/e = 10/0.07 = 142.86 N/M
The spring constant is therefore:
= 142.86 N/M
ananyardandekar2002:
The decimal points seems incorrect..
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