Question

A 40-kg ball is pulled to one side until it is 1.5 m above its lowest point. What will be its velocity as it passes through its lowest point?
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Answer 1

Answer:

the potential energy at the high point is equal to the kinetic energy at the low point

m g h = 1/2 m v^2 ... v = √(2 g h)

the mass is in kilograms , so the height is probably in meters

v = √(2 * 9.8 * 1.5) m/s

Answer 2

Answer:

the potential energy at the high point is equal to the kinetic energy at the low point

m g h = 1/2 m v².

v = $\sqrt{2gh}$

the mass is in kilograms , so the height is probably in meters

v = √$\sqrt{2*9.8*1.5}$ m/s

v=5.42217 m/s

Explanation:

Potential energy is defined as mechanical energy, stored energy, or energy caused by its position. The energy that a ball has when perched at a top of a steep hill while it is about to roll down is an example of potential energy.

the formula of potential energy

U= mgh

where

U= gravitational energy

m= mass

g = gravitational field

h = hight

so the velocity v = 5.422m/s

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