Question

a 40 kg ball moving at 20 ms strike centrally another ball at rest weighing 50 kg .calculate the velocity of each after impact and the loss of kinetic energy 1)when they stick together 2)the collision is perfectly elastic​

Answer 1

Answer:

6cm/sec

Explanation:

Let their velocities after the collision be v1 

and v2. As we know for elastic collision. 

Relative velocity of approach = relative velocity of separation

10−4=v2−v1⇒6=v2−v1

⇒v1=v2−6

Applying conservation of momentum,

10×10+5×4=10v1+5v2

120=10v1+5v2

120=10(v2−6)+5v2=15v2−60

15v2=180⇒v2=12cm/sec

v1=6cm/sec