Question

A 40 kg block accelerates by force of 200N. acceleration of the block is 3 m/s^2 determine the magnitude of friction force fg experienced by the block​

Answer 1

Given :

Mass of block = 40kg

Applied force = 200N

Acceleration of the block = 3m/s²

To Find :

Magnitude of friction force experienced by the block.

Solution :

❒ As per newton's second law of motion, force is measured as the product of mass and acceleration.

Mathematically, F = m × a

• F denotes force
• m denotes mass
• a denotes acceleration

We can use this formula only when friction is absent. In this question, friction force opposes the forward motion.

Therefore the equation will be,

• F - f = ma

where f denotes friction force

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By substituting the given values;

➙ F - f = ma

➙ 200 - f = (40)(3)

➙ 200 - f = 120

➙ f = 200 - 120

➙ f = 80 N

Answer 2

$\huge\colorbox{yellow}{Áηѕωєя࿐❤}$

Given :

Mass of block = 40kg

Applied force = 200N

Acceleration of the block = 3m/s²

To Find :

Magnitude of friction force experienced by the block.

Solution :

❒ As per newton's second law of motion, force is measured as the product of mass and acceleration.

Mathematically, F = m × a

• F denotes force
• m denotes mass
• a denotes acceleration

We can use this formula only when friction is absent. In this question, friction force opposes the forward motion.

Therefore the equation will be,

• F - f = ma

where f denotes friction force

By substituting the given values;

➙ F - f = ma

➙ 200 - f = (40)(3)

➙ 200 - f = 120

➙ f = 200 - 120

➙ f = 80 N

Hope it helps :)