A 40 kg can of paint rest on ledge 20 m above the ground. A taut rope attached to the can passes over a pulley and straight down to a 3.0 kg can of nails. If the can of paint is accidentally knocked of the ledge, how much time does a carpenter have in order to catch the can of paint before it smashes on the ground?
Answers
Answered by
1
Answer:
it takes time of 9 seconds only
Answered by
5
Thus the time required is t = 5.345 s
Explanation:
- t = ?
- d = 20m
- Vi = 0m/s
- d = Vit*(1/2)at^2
- t = √ (2d/a)
a = ?
a = Fnet/mnet
m1 = 4kg
m2 = 3kg
a = Fnet/mnet
= (Fg1 - Fg2)/(m1 + m2)
= (m1g - m2g)/(m1+m2)
= g(m1-m2)/(m1+m2)
= 9.81m/s^2(4kg-3kg)/(4kg+3kg)
= 9.81mkg/s^2/7kg^2
a=1.4m/s^2
t = √(2d/a)
d = 20m
a = 1.4m/s^2
t = √(2(20m)/1.4m/s^2)
= √40m/1.4m/s^2)
t = 5.345 s
Thus the time required is t = 5.345 s
Similar questions