Question

a 40 kg shell is moving at velocity of 72 kilometres per hour it explodes into two pieces one of mass 15 kg stops. calculate the velocity of the Other piece

Answer 1

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Here's ur answer ⤵⤵⤵

Mass of the shell, M =40kg

Speed of the shell, U=72km/h=20 m/s

Initial momentum of the shell, Pi=Mu=(40)(20)=800-m/s

After it breaks,the masses of the parts are 15 kg and 25 kg.

The 15 kg piece stops. Let the speed of the piece be "v".

So, total momentum after breaking part Pf= (15) (0) + (25) (v) =25v.

Now , by the law of conservation of momentum , Pf=Pi

=>25v = 800

=> V=800/25=32 m/s

This is the speed of the other piece => 32 m/s

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Answer 2

→ Formula,

»m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

› m = 40kg

› u = 72km/hr =20m/s

» m₁= 15kg

›v₁ = 0

» m₂ = 40-15= 25kg

→we need to find v₂

» Therefore,

› 40×20 = 15×0+25×v₂

› 800 = 25v₂

» v₂ = 32

∴ The speed of the other will be 32m/s