Physics, asked by NithinKrishnaR, 6 months ago

A 40 kg slab rests on a frictionless floor. A 10 kg
block rests on top of the slab. The coefficient of
friction between the block and the slab is 0.40. The
10 kg block is acted upon by a horizontal force of
100 N. If g = 10 m/s2, the resulting acceleration of
the slab will be
100 N
10 kg
40 kg

Answers

Answered by NarutoxAnbuxBlackopp

Answer:

A 10 kg block rests on top of the slab. The static coefficient of friction between the block and the slab is 0.60 while the kinetic coefficient is 0.40. The 10 kg block is acted upon by horizontal force 100 N.

Explanation:

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A 40 kg slab rests on a frictionless floor. A 10 kgblock rests on top of the slab. The coefficient offriction between the block and the slab is 0.40. The10 kg block is acted upon by a horizontal force of100 N. If g = 10 m/s2, the resulting acceleration ofthe slab will be100 N10 kg40 kg​

Answers

A 40 kg slab rests on a frictionless floor. A 10 kg
block rests on top of the slab. The coefficient of
friction between the block and the slab is 0.40. The
10 kg block is acted upon by a horizontal force of
100 N. If g = 10 m/s2, the resulting acceleration of
the slab will be
100 N
10 kg
40 kg