Question

A 40-kilogram person is standing on one foot. The area of the foot is 0.02 square meters. What is the pressure exerted by the foot on the floor?

Answer 1

Answer:

Explanation:

Hi,

Weight of the man = mg = 20 × 10 = 200 N

(i) When man is standing on both his feet,

Area in contact, A = 2 × 0.01 m2 = 0.02 m3

Pressure on the floor = P = F/A =200/0.02 = 1 × 104 m2

(ii) When man is standing on one feet,

Area in contact, A = 0.01 m2 = 0.01 m3

Pressure on the floor = P = F/A =200/0.01 = 2 × 104 m2

Answer 2

Answer:

19600Nm^-2

Explanation:

As we know pressure= force/area

force = 40 kg*9.8=392 newtons

area = 0.02 m^2

pressure= 392/0.02

              = 19600 Nm^-2