Math, asked by kritikadiii98, 1 year ago

a 40 litres of mixture of milk and water contains milk and water in a ratio 3:2 respectively. 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more. at the end of the two removals and replacement, what will be the ratio of milk and water in the resulting mixture?

Answers

Answered by prabhhere
9

Answer:

Step-by-step explanation:

Mixture = 40 Litres

Milk = 40 * 3/5 = 24 Litres

Water = 40 - 24 = 16 Litres

Replacement 1:

Mixture = 30 Litres

Milk = 30 * 3/5 + 10 = 28 Litres

Water = 40 - 28  = 12 Litres

Ratio = 7:3

Replacement 2:

Milk = 28 - 7 + 10 = 31 Litres

Water = 12 - 3 = 9 Litres

Final Ratio = 31/9

Answered by RvChaudharY50
21

Answer:

FC = 40(1-1/4)²

FC = 40*3/4*3/4 = 22.5 litre (Water)

Required ratio , now = 17.5 : 22.5 = 7:9 (Ans)

(Mark as brainlist)

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