Question

A 40 ml of a mixture of h2 and o2 at 18 c and 1 atm pressure was sparked so that the formation of water was complete.the remaining pure gas had a volume of 10 ml at 18 c and 1 atm pressure.if the remaining gas was h2,the mole fraction of h2 in the 40 ml mixture is

Answer 1

we can use PV= NRT to obtain no.of moles

Answer 2

                                                   H2   +    12O2    →    H2OVolume before reaction           a                 b                  0Volume after reaction              a−2b         0                  bNow, a+b=40and, a−2b = 10On solving the above two equations we get, a=30 mL and b=10 mLNow, mole fraction of H2=aa+b3030+10=0.75