Question

A 40 N block exerts 20 pa of pressure on a table .what is thecarea of the block that is touching the table

Answer 1

Answer:

2 m²

Explanation:

Given :

• Force exerted by the block = 40 Newtons

• Pressure exerted by the block = 20 pascals

To find :

• Surface area of the block in contact with the table

Pressure = force / area

Substituting the values :

$20 = \frac{force}{area}$

20 = 40/Area

20×Area = 40

Area = 40/20

Area = 2 m²

The surface area of the block which is in contact with the table is equal to 2 m²

Answer 2

Answer:

$2m^{2}$

Explanation:

Given:

Pressure = 20 pa

Force = 40 N

Area = To Find

Solution:

$Pressure = \frac{Force}{Area}\\\\20 = \frac{40}{area}\\\\area = \frac{40}{20}\\\\Area = 2m^{2}$

. . . . . Hope it Helps . . . . .

By:

AnswerMe314