Question

A 40 N block exerts 20 Pa of pressure on table what is the area of the block this is touching the table​

Answer 1

Step-by-step explanation:

P = T / A

thrust is equal to force

p= F / A

A= F / p

A= 40/20

A=2 CM square

Answer 2

Given,

A 40 N block exerts 20 Pa of pressure on the table.

To Find,

What is the area of the block that is touching the table​?

Solution,

We can solve the question as follows:

It is given that a force of 40 N exerts 20 Pa of pressure on the table. We have to find the area of the block that is touching the table​.

$Force = 40\: N$

$Pressure = 20\: Pa$

Now, the pressure exerted by a force on an area is given as:

$Pressure = \frac{Force}{Area}$

$20 = \frac{40}{Area}$

$Area = \frac{40}{20}$

$Area = 2\: m^{2}$

Hence, the area of the block touching the table is 2 m^2.