: A 40 N object has fallen 4m and is 6m above the ground .its K.E in joules will be?
Answers
Answered by
11
As the body has fallen 4m, therefore h= 4m
Now,
h= 4m
u=0m/s
g= 10 m/s²
v= ?
v²-u²=2gh
v²= 2×10×4= 80
v= √80
Kinetic Energy = 1/2mv²
= 1/2×40×{√80}²
= 1/2×40×80= 1600 J
Hope it helps! Please mark it as 'Brainliest'!!
Now,
h= 4m
u=0m/s
g= 10 m/s²
v= ?
v²-u²=2gh
v²= 2×10×4= 80
v= √80
Kinetic Energy = 1/2mv²
= 1/2×40×{√80}²
= 1/2×40×80= 1600 J
Hope it helps! Please mark it as 'Brainliest'!!
Answered by
27
Since the body cover the distance 4m so
S= h= 4m
g=10m/s^2
mg= 40N
so,m= 4 kg
now v^2 - u^2 = 2aS
v^2 - u^2 = 2gh
v^2 - (0)^2 = 2*10*4
v^2 = 80
we know that
K.E = 1/2 mv^2
K.E = 1/2* 4* 80
K.E = 2*80 [1/2*4 = 2]
K.E= 160 joules
:-)
S= h= 4m
g=10m/s^2
mg= 40N
so,m= 4 kg
now v^2 - u^2 = 2aS
v^2 - u^2 = 2gh
v^2 - (0)^2 = 2*10*4
v^2 = 80
we know that
K.E = 1/2 mv^2
K.E = 1/2* 4* 80
K.E = 2*80 [1/2*4 = 2]
K.E= 160 joules
:-)
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