Question

a 40 ohm elctric heater is connected to 200v , 50 hz main supply,the peak value of electric current in the circuit is​

Answer 1

Given, Resistance (R) =40ohm

potential difference (V) =200v

we know that,

V=IR

(current) l = V/R

I=200/40

I=5 (amp)

current in the circuit is 5 ampere

Answer 2

The peak value of electric current in the circuit is​ 7 A.

Explanation:

The resistance of the electric heater is 40 ohm.

The peak value of current is given as

$i_{peak} =\frac{v_{peak} }{R}$

Here, $V_{peak}$ is the peak voltage in the circuit and R is the resistance.

Also, the peak voltage and Vrms voltage related as

$V_{peak}=V_{rms} \sqrt{2}$

Given $V_{rms} =200V$.

Therefore,

$V_{peak} =200V\times\sqrt{2}$

$V_{peak}=282.84 V =283 V$

Substitute peak voltage value, in above equation, we get

$i_{peak} =\frac{283 V}{40\omega}$

$i_{peak} =7.075 =7 A$

Thus, the peak value of electric current in the circuit is​ 7 A.

#Learn More: peak current.

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