Physics, asked by jcpamzkie6012, 1 day ago

A 400-gram package lying on a horizontal surface is attached to a horizontal string that passes over a smooth pulley. When a mass of 200 grams is attached to the other end of the string, the package is on the point of moving. Find , the coefficient of friction.
please explain it as well! i'm a 9th grader, and thank you :)

Answers

Answered by siddharth6395
0

Answer:

M1*g = 0.4 * 9.8 = 3.92 N. = Wt. of pkg

Explanation:

M1*g = 0.4 * 9.8 = 3.92 N. = Wt. of pkg.= Normal force(Fn).

Fp = 3.92*sin 0 = 0 = Force parallel to the surface.

= M2*g = 0.2 * 9.8 = 1.96 N. = Force applied.

Fs = us*Fn. = 3.92us.

&-Fp-Fs = M*a.

1.96-0-3.92us = M*0 = 0, us = 0.50.

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