⦁ A 400 gram soccer ball, initially at rest, is kicked. Upon contact with the ball, the foot exerts 1000 N of force, thus causing the ball to leave the foot at 30 m/s. Based on the info, how long was the foot in contact with the ball?
show your work and the formula
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Answer:
0.012 sec or 1.2×10² sec
Explanation:
Using Newton's second law of motion,we get
F=ma
=>1000N=400×a
=>a=1000/0.4 (because 400g=0.4kg) =2500m/s²
Now,
u=0. (because the ball was initially at rest)
v=30m/s. (given)
a=2500 m/s²
Using first equation of motion we get,
v=u+at
=>30=0+2500t
=>t=30/2500= 0.012 sec
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