Physics, asked by rukminiramesh1967, 5 months ago

A 400 kg car from rest attains a speed of 50 m/s in 20 s. Find the power developed in the engine​

Answers

Answered by noor5468
0

Answer:

power = work/time use this formula u get ans

Answered by AadityaSingh01
7

Given:-

  • Mass of car ( m ) = 400 kg

  • Initial velocity of car ( u ) = 0 m/s

  • Final velocity of car ( v ) = 50 m/s

  • Time elapsed ( t ) = 20 sec

To Find:-

  • Power developed in the engine.

Solution:-

Here, Power = \dfrac{W}{t}                  Where, W = work-done,

                                                            t = time elapsed

Now, Work-Done = F × S                       Where,  F = Force

                                                                              S = Displacement

So, Force applied by engine ⇒ m × a

                                                ⇒ 400 × \bigg(\dfrac{50  - 0}{20}\bigg)

                                                ⇒ 1000 N

∵ Acceleration of car ( a ) ⇒ \bigg (\dfrac{v - u}{t}\bigg)

                                          ⇒ \bigg (\dfrac{50 - 0}{20}\bigg)

                                          ⇒ \dfrac{5}{2} m/s²

Now, By second equation of motion

S = ut + \dfrac{1}{2}at^{2}

S = 0 \times 20 + \dfrac{1}{2} \times \dfrac{5}{2} \times 20 \times 20

S = \dfrac{1}{2} \times \dfrac{5}{2} \times 20 \times 20                             [ If any number is multiplied with 0 it product will be 0]

S = 500 \ m

So, Work-Done ⇒ F × S

                          ⇒ 1000 N × 500 m

                          ⇒ 5,00,000 joule

∴ Power of the Engine ⇒ \dfrac{W}{t}

                                      ⇒ \dfrac{5,00,000}{20}

                                      ⇒ 25,000 watt

We know that 1kW = 1000 watt

         25,000 watt = \dfrac{25,000}{1000} = 25 kW

                         

Hence, Power developed in the Engine is 25,000 watt or 25kilowatt.

Some Important terms:-

  • Power = \dfrac{W}{t}

  • Work-Done = F × S

  • Kinetic Energy = \dfrac{1}{2}mv^{2}

  • Potential Energy = mgh                       Where, m = mass of the body

                                                                           g = acceleration due to gravity

                                                                             h = height from the ground

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