A 400kg satellite is in a circular orbit of radius 2R about the earth. how much energy is
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2
Answer:E
i
=
4R
e
−GM
e
.m
E
f
=
8R
e
−GM
e
m
Energy required =
8R
e
−GM
e
m
+
4R
e
GM
e
m
=
8
g.mR
e
=3.13×10
9
J
K.E will become half & P.E will become twice.
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