A 400V, 3ph supply connected to 3 wire star connected load. The branch mpedances of the load are-Zph=4+j8) ohms per phase. Find the voltage across each phase impedanc
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Y connection, voltage applied across each impedance = 400/√3 so phase current = V/Z=400/10√3= 40/√3 amps
Power in each phase = Phase voltage x phase current = 400/√3 x 40/√3 = 1600/3 VA
Total power(three phases) = 1600/3 × 3 =1600 VA or 1.6 kVA
Active power can be calculated if load angle of 10 ohm impedance is known.
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