Question

A 40g sample of KOH containing inert impurities, is treated with 300ml of 0.9M H2SO4 solution. The resulting solution is found to react with 150ml of 0.1M NaOH solution. Calculate % purity of sample...​

Answer 1

Answer:

hii here is your answer

Explanation:

ANSWER

H

2

SO

4

+2NaOH→Na

2

SO

4

+2H

2

O

Moles of NaOH required =

1000

2×84.5

=0.169

For 2 moles NaOH→1 mole H

2

SO

4

is used

For 0.169 mole NaOH→0.0845 moles are used.

Mass of H

2

SO

4

→0.0845×98=8.281 gm (Theoretical)

Mass of H

2

SO

4

used in original reaction ⇒5×1.8=9 gm

∴ % purity =

9

8.281

×100=92.12 %