Question

A 40kg boy sits 1.2m from the fulcrum of a see saw. Where should another boy of 30kg sit on the other side in order to make it balance.​

Answer 1

Answer:

4534cm

Explanation:

Answer 2

⠀⠀⠀⠀Answer :-

Another boy sits 1.6 m from the fulcrum.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \pink{Explanation:}$

Given that,

Mass of boy = 40 kg

Distance = 1.2 m

Mass of boy = 30 kg

Let the distance from the fulcrum where the another boy sit be x.

We need to calculate the another side

The moment of force on both side of the fulcrum must be same to the balance.

$\sf{F\times d=F'\times d'}$

$\sf{mg\times d=m'g\times d'}$

$\bf{Put \: the \: value \: into \: the \: formula}$

$\sf{40\times9.8\times1.2=30\times9.8\times x}$

$\sf{x=\dfrac{40\times9.8\times1.2}{30\times9.8}}$

$\bf{x=1.6\ m}$

$\mathfrak{Hence, Another \: boy \: sits \: 1.6 m \: from \: the \: fulcrum} \: \huge\green{✓}$

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