Question

A 40kg of shell is moving with a velocity of 72km/h .It explodes into two pieces ,of which one piece of mass15kg stops immediately calculate the velocity of the other piece

Answer 1

conservation of momentum => 160m/s

Answer 2

→ Formula,

»m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

› m = 40kg

› u = 72km/hr =20m/s

» m₁= 15kg

›v₁ = 0

» m₂ = 40-15= 25kg

→we need to find v₂

» Therefore,

› 40×20 = 15×0+25×v₂

› 800 = 25v₂

» v₂ = 32

∴ The speed of the other will be 32m/s