Question

A 40kW electric cable is used to transmit electricity through a resistor of resistance 2ohms at 800v the power loss as internal energy is

Answer 1

is this question complete.....?

Answer 2

P= V^2 ÷ R

40 x 1000 = (800 x 800) ÷ R

R = (800 x 800) ÷ (40 x 1000)

R = 16 ohm

I = V/R

I= 800 ÷ 16

I= 50 Amps

Power Loss across 2 ohm Resistor = I^2 x R

= (50 x 50) x 2

= 5000 Watts

= 5 KW