A 40L balloon is filled with gas at 4 atm. What will be it’s new volume at standard pressure of 1 atm?
Answers
Answer:
The new volume of the balloon at 1 atm is 160 L.
Explanation:
This problem can be solved by applying the Boyle's Law.
Boyle's law is a gas law that shows the relationship of volume and pressure of a gas. This law states that the pressure of a gas is inversely proportional to its volume at constant temperature.
The mathematical equation for this law is:
P₁V₁ = P₂V₂ where
P is the pressure and V is the volume
The condition with subscripts 1 are the initial conditions
While the condition with subscripts 2 are the final conditions
This equation will be used to get the new or final volume that the problem is asking for.
Given:
P₁ = 4 atm
V₁ = 40 L
P₂ = 1 atm
Required:
V₂
Solution:
P₁V₁ = P₂V₂
Rearranging the equation above to solve the new volume (V₂), we have,
V₂ =
V₂ =
V₂ = 160 L
We can see from the unit analysis that upon applying the operation (multiplication and division), the unit atm will cancel out and we are left with the unit liters (L). This unit is the unit for volume, and this is correct because we are looking for the new volume of the balloon.
Therefore, the new volume of the balloon at 1 atm is 160 L
Answer:
Explanation:
P1V1=P2V2 => V2=P1V1/P2 =>
V2= 4×40/1 => V2=160L (will be tne new value of the volume at 1 atm)