Question

A 40N force is applied on a 2 kg block placed on a rough
inclined plane having angle of inclination 60° with
horizontal. If coefficient of friction is 0.4, find the work
done by frictional force when the displacement of block
is 2 m.
F = 40N
600​

Answer 1

Answer:

-8J

Explanation:

firstly the proper neat diagram will surely help then do components of

mg and then simply apply formula of WD = force × displacement

see my attachment