Question

A 41. A particle A has charge + q and particle B has charge + 4q with each of them having the same mass m. When allowed to fall from rest through same electrical potential difference, the ratio of their momenta will be​

Answer 1

Answer:

B

1 :2

Particle A Particle B

Charge =q Charge =4q

mass=m mass=m

potential=V

A

potential=V

B

Now, kinetic energy, K=charge ×potential

=qv

and kinetic energy =

2

1

mv

2

∴

K

B

K

A

=

4qv

qv

=

2

1

mv

B

2

2

1

mv

A

2

or,

V

B

V

A

=

2

1

Hence Option B is correct .