A 42.5 kW engine has a mechanical efficiency of 85%. Find the indicated power.
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Answer:
36.125 kW
Explanation:
Let's consider power working for 85% as W
As given, W= 42.5 kW (max power)
Engine has an efficiency of 85 %
Therefore, W'÷W=85÷100
W'=(85×42.5kw)÷100 = 36.125k W
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