A 42kg block of ice moving an rough horizontal surface stops due to friction, after some time. If the initial velocity of the decelerating block is 4m/s, the mass of ice in (kg) that has melted due to heat generated by friction is : (latent heat of ice is 3.36x105 J/kg)
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2
Answer:
The change in the kinetic energy of the ice is,
2
1
mv
2
This energy is required to melt the ice.
2
1
×42×4
2
=m
′
×3.36×10
5
Thus, m' = 1 g
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