Question

A 430 resistor, a 210 resistor, and a 100 resistor are all in parallel. The total resistance is :

Answer 1

Answer:

Explanation:

Let

$R_{1} = 430\\R_{2}=210\\R_{3}= 100$

$\frac{1}R_{p} = \frac{1} R_{1}+ \frac{1}R_{2}+ \frac{1}R_{3}$

solving it we get,

$\frac{1}R_{p} = \frac{1}{430} + \frac{1}{210} + \frac{1}{100}$

solving it we will get the required answer.

Answer 2

Answer:

the resistance is 58.82 ohm