Question

a 450 g mass on spring is oscillating at 1.2Hz with total energy 0.51J

Answer 1

Answer:

A=0.199

Explanation:

A=0.199

Explanation:

We are given that

Mass of spring=m=450 g==\frac{450}{1000}=0.45 kg=

1000

450

=0.45kg

Where 1 kg=1000 g

Frequency of oscillation=\nu=1.2Hzν=1.2Hz

Total energy of the oscillation=0.51 J

We have to find the amplitude of oscillations.

Energy of oscillator=E=\frac{1}{2}m\omega^2A^2E=

2

1

mω

2

A

2

Where \omega=2\pi\nuω=2πν =Angular frequency

A=Amplitude

\pi=\frac{22}{7}π=

7

22

Using the formula

0.51=\frac{1}{2}\times 0.45(2\times \frac{22}{7}\times 1.2)^2A^2

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