Question

A 45KW broadcasting antenna emits radio waves at a frequency of 4MHz .How many are emitted per second ?

Answer 1

Answer:

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Explanation:

number of photons emitted per second =

n = Power / Energy of Photons

= P/ hv

= 66000/ (6.634* 10^-34 * 10^6) = 9948 * 10^28 = 10^31photons approx