Physics, asked by anjireddysrdhar1983, 8 months ago

a 46²
has four
A physical quantity y=
observable
d
in a,b,c and d are 20%,3%,4%&
error
The percentage
5% respectively - find the enor?​

Answers

Answered by smahender153
1

Answer:

The given physical quantity A=

c

d

a

2

b

3

Given :

a

Δa

×100=1%,

b

Δb

×100=3%,

c

Δc

×100=2% and

d

Δd

×100=2%

Percentage error in A,

A

ΔA

×100= 2

a

Δa

×100 +3

b

Δb

×100 +

c

Δc

×100+

2

1

×

d

Δd

×100

A

ΔA

×100=2×1+3×3+2+

2

1

×2=14 %

Explanation:

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