Question

(a) 4695
(c) 4285
(b) 4593
(d) 4387
13. 4183, 4388, 4285, 4490, ? ,4592​

Answer 1

Answer:

the alternate numbers are in series i.e

4183,4285,?......(1)

4388,4490,4592....(2)

4285-4183 =102

4490-4285 = 102

therefore in both series 102 is added.

we have to find ? so we need only 1 st series.

4285+102 = 4387

therefore option (d) is the answer.

hope it helps you.

Answer 2

Answer:

4183 + 205 = 4388

4388 - 103 = 4285

4285 + 205 = 4490

4490 - 103 = 4387

4387 + 205 = 4592

so answer is 4387