a+4b=50 and a+49d=5 then a+24d= in A.P
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elimination method lga k a and d ki value nikal ke put krle bro
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Answer:
by substitution method
a + 4d = 50. eq-(1)
a + 49d = 5. eq-(2)
substitute the eq (1)
a = 50 - 4d. eq-(3)
put the value of eq (3) in eq (2)
a + 49d = 5. eq-(2)
50 - 4d + 49d = 5. (a = 50 - 4d)
50 - 45d = 5
- 45d = - 45
d = -45/-45 = 1
put the value of d = 1 in eq (3).
a = 50 - 4d
a = 50 - 4(1)
a = 50 - 4
a = 46
now,
a + 24d = ?
46 + 24(1) = ? ( a = 46, d = 1)
46 + 24 = 70
so the answer is 70.
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