a+4b+8c and 4a+8b+c addition
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Answered by
1
Answer:
After adding we get:
(3a−4b+4c)+(2a+3b−8c)+(a−6b+c)
=3a+2a+a−4b+3b−6b+4c−8c+c
=6a−7b−3c
Answered by
0
Answer:
5a + 12b + 9c
Hope this answer helps you
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