A 4cm cube has its upper face displaced by 0.1 mm by a tangential force of 8kN . calculate the shear modulus of the cube
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Answer:
L = 4cm
a = L^2 = 16sq.cm
displacement ,Delta L = 0.1mm = 0.01 cm
force applied , F = 8KN = 8000 x 10^5 = 8 x 10 ^8
as , G = FL / a delta L
= 8 × 10 ^8 x 4 / 16 × 0.01
= 2 x 10 ^10
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Explanation:
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