Question

a = 4i+3j+k b= i-2k, find magnitude of 2b x a

Answer 1

Answer:

6k - 6j

Explanation:

a = 4i+3j+k , b= i-2k , 2b x a = ?

2b = 2i-4k

2b × a = (2i-4k)×(4i+3j+k)

= (2i * 4i + 2i * 3j + 2i * k) - 4k*4i - 4k*3j -4k * k

= (0 + 6k - 2j ) - 4j -(-12j) - 0

= 6k - 2j -4j +12j

= 6k - 6j

Answer 2

Cross product, $2B\times A=-4i-2j+22k$

Explanation:

Given that,

Vector 1, $A=4i+3j+k$

Vector 1, $B=i-2k$

To find,

2B x A

Solution,

Firstly, we can find the twice of B. So,

$2B=2(i-2k)=2i-4k$

Now finding the cross product of 2B and A, we get :

$2B\times A=(2i-4k)\times (4i+3j+k)$

$2B\times A=\begin{pmatrix}-4&-2&22\end{pmatrix}$

$2B\times A=-4i-2j+22k$

Hence, this is the required solution.

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