A 4kg block is placed at the top of 8kg block which rests on smooth table.4kg block slips on 8kg when a force of 20N is applied on 4kg . The maximum horizontal force required to make both blocks move together is
Answers
Answered by
25
20 = 4a
a = 5ms⁻²
F = (m₁ + m₂)a
F = (4+8)5
F = 60 N
a = 5ms⁻²
F = (m₁ + m₂)a
F = (4+8)5
F = 60 N
Attachments:
Similar questions