Question

A 4kg body is moving horizontally with speed of 5m/s to increase it speed to 10m/s the amount of work required to be done on this body is ?

Answer 1

Answer:

The change in kinetic energy of the body is

\begin{gathered} \frac{1}{2} \times 4 \: \times ( {10}^{2} - {5}^{2}) \\ = 2 \times (100 - 25) \\ = 2 \times 75 \\ = 150\end{gathered}

2

1

×4×(10

2

−5

2

)

=2×(100−25)

=2×75

=150

Thus , The required work done = The change in the kinetic energy of the body = 150J

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