A 4kg brick is dropped from the top of a building whose height is 30m. What is the velocity with which it reaches the ground?
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Answer:
The velocity with which it reaches the ground is 24.25 m/s.
Explanation:
Given :
A 4 kg brick is dropped from the top of a building whose height is 30 m.
To find :
the velocity with which it reaches the ground.
Solution :
The initial velocity of the brick is 0 m/s as it is dropped.
Let the velocity with which it reaches the ground be v m/s.
Here, the acceleration, a = g
Using v² - u² = 2as :
v² - 0² = 2 × g × s
v² = 2 × 9.8 × 30
v² = 196 × 3
v = √(196 × 3)
v = 14√3
v = 24.25 m/s
Therefore, the velocity with which it reaches the ground is 24.25 m/s.
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