A 4kg object is moving horizontal with a speed of 5 m/s to increase its speed to 10m/s the amount of net work required to done on this object is
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m=4kg
u=5m/s
v=10m/s
according to work energy theroum
w=1/2m(v^2-u^2)
w=1/2×4(10^2-5^2)
w=1/2×4(100-25)
w=2×75
w=150j
u=5m/s
v=10m/s
according to work energy theroum
w=1/2m(v^2-u^2)
w=1/2×4(10^2-5^2)
w=1/2×4(100-25)
w=2×75
w=150j
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